loadhost.blogg.se - Sas list directory contents

#SAS LIST DIRECTORY CONTENTS CODE#
#SAS LIST DIRECTORY CONTENTS FREE#

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#SAS LIST DIRECTORY CONTENTS FREE#

Return the value as the result of the macro.Sites/iias/iias04/Lists/b6/Attachments/74Īsean free Trade Area: Discriminatory or Not? A case Study for Vietnam and Singapore %if (0=%sysfunc(filename(fileref,&path))) %then %do Otherwise set SYSRC=1 to mean that PATH exists but is not a directory. %if ^%sysfunc(fileexist(&path)) %then %goto quit %if (%bquote(&path) = ) %then %goto quit If path is not specified or does not exist then return normal failure. Set up return values as normal failure to find path.

Global macro variable SYSRC will be set to 1 when a file is found (path /* Name of directory to test for existance */ This will tell you if the file is a directory.įor example here is the function style macro that I use. Then use the DOPEN() function to attempt to open the fileref as a directory.

#SAS LIST DIRECTORY CONTENTS CODE#

This will return a code to indicate if the file exists or not. Use FILENAME() function to define a fileref to the file. * this macro collects some additional fileinformation from all file in macrovariable fpath and creates a HTML-Ouput*/ Select filepath into: fpath separated by '#' from x *this part just makes a macrovariable with all results*/ Here a part of my code which i am using: filename _folder_ "%bquote(&mydirectory/)" įilepath="&mydirectory"||dread(handle,i) Open an filehandle and do a finfo, this returns a warning if it is not a file, butĪ)maybe it could be something else then a directory or file, or a warning because of other reasonsī)checking for a warning to detect type is not a good solution imo

using unixfunctionalities in sas: This is forbidden on our server, so no option for me.

There could be files without extensions (and so dont have a dot) and also directories which have a dot in name, so this is not foolproof

using fileexists: This returns true for files and directories, so this does not work here.

I tried some things and had some Ideas, but non is really foolproof, maybe someone can give me a hint how i can get this. Problem is, my datastep only returns the name of the object, but not an information if this is a file or directory.

I have a small STP which list all files/subdirectories in a given directory on our Unix-Server.